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A uniform chain of length L and mass M i...

A uniform chain of length `L` and mass `M` is lying on a smooth table and one-third of its length is hanging vertically down over the edge of the table. If g is the acceleration due to gravity, the work required to pull the hanging part on to the table is

A

MgL

B

MgL/3

C

`MgL//9`

D

`MgL//18`

Text Solution

Verified by Experts

The correct Answer is:
D

`W = (MgL)/(2n^(2)) = (MgL)/(2(3)^(2)) = (MgL)/(18)` (n = 3 given)
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