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cos^(2)(""(pi)/(6) + theta ) -sin^(2)""(...

`cos^(2)(""(pi)/(6) + theta ) -sin^(2)""((pi)/(6) - theta ) = `

A

`(1)/(2)Cos2theta`

B

`-(1)/(2)Cos2 theta`

C

0

D

1

Text Solution

Verified by Experts

The correct Answer is:
A
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