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If sec A tan B + sec B tan A = 91 then t...

If sec A tan B + sec B tan A = 91 then the value of `(secA secB + tanA tan B)^(2) - 91^(2)` is equal to

A

1

B

-1

C

0

D

None of these

Text Solution

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The correct Answer is:
A
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Knowledge Check

  • tan 2A- sec A sin A =

    A
    `sin A* tan 2A`
    B
    `tan A * sec 2A`
    C
    `sec A - sin 2A `
    D
    `cos A- cot 2A `
  • If sec x + sec^(2) x = 1 then the value of tan^(8) x - tan^(4) x - 2 tan^(2) x +1 will be equal to 0

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    0
    B
    1
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    2
    D
    3
  • (sec A + tan A -1) (sec A - tan A+1)=

    A
    `2 sin A `
    B
    `2 cos A `
    C
    `2 sec A `
    D
    `2 tan A `
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