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If theta = (11pi)/(6). Then cos theta + ...

If `theta = (11pi)/(6)`. Then `cos theta + sin theta` =

A

`(sqrt(3) + 1)/(sqrt(2))`

B

`(sqrt(3)-1)/(sqrt(2))`

C

`(sqrt(3)-1)/(sqrt(2))`

D

`(sqrt(3)+1)/(2)`

Text Solution

Verified by Experts

The correct Answer is:
C
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AAKASH SERIES-TRIGONOMETRIC RATIOS-ADDITIONAL PRACTICE EXERCISE (LEVEL - II) (PRACTICE SHEET (ADVANCED) SIGNLE ANSWER TYPE QUESTIONS)
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