Two points are located at a distance of 10 m and 15 m from the source of wave. The period of oscillation is 0.05 sec and the velocity of the wave is 300 m/sec. What is the phase difference between the oscillations at two points ?.

Options

A. `pi/3`
B. `(2pi)/(3)`
C. `pi`
D. `(pi)/(6)`

Answer

B

Explanation

For given wave, `v = f lamda = ( lamda)/(T)`
`therefore lamda = v T = (300) (0.05) = 15 m`
Phase difference between two particles separted by distance `Delta x` is,
`Deltaphi = (2pi)/(lamda) Delta x`
`= (2pi)/(15) (15-10)`
`= (2pi)/(3) rad `