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Each of the two strings of length 51.6 c...

Each of the two strings of length 51.6 cm and 49.1 cm are tensed separately by 20 N force. Mass per unit length of both the strings is same and equal to 1 g/m. When both the strings vibrate simultaneously the number of beats is ......

A

7

B

8

C

3

D

5

Text Solution

Verified by Experts

The correct Answer is:
A
Here frequency of vibration of string is,
`f =(1)/( 2L ) sqrt ((T)/( mu ))`
`therefore f _(1) = (1)/( 2 (0.516)) sqrt ((20)/( 0.001)) = 144 Hz`
`therefore` Beat frequency `f _(2) - f _(1) = 144 - 137 =7 Hz`
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