A transverse wave is represented by `y = Asin(omegat - kx).` For what value of the wavelength is the wave velocity equal to the maximum particle velocity ?

Options

A. `(piA)/(2)`
B. `piA`
C. `2piA`
D. `A`

Answer

C

Explanation

Here y = `A sin(omega t -kx),`
Moreover `v _(max) =v ` (Given)
`therefore A omega = (omega )/(k)`
`therefore A = (1)/( k ) = (lamda )/( 2pi // lamda) = (lamda)/( 2pi )`
`therefore lamda = 2pi A`