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If (1)/(8!)+(1)/(9!)=(x)/(10!), find x....

If `(1)/(8!)+(1)/(9!)=(x)/(10!)`, find x.

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KUMAR PRAKASHAN-OBJECTIVE SECTION AS PER NEW PAPER SCHEME -Permutations and Combinations (Fill in the blanks )
  1. ............are the numbers of words using the letters of word ROSE wi...

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  2. Evaluate (n!)/(r!(n-r)!), when n = 5, r = 2.

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  3. If (1)/(8!)+(1)/(9!)=(x)/(10!), find x.

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  4. 6P3 - 5P2 = ......... .

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  5. (nP4)/((n-1)P4) =5/3 then n = ......... (where n gt 4 )

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  6. If (n +1 ) ! = 12 (n-1) ! then n = ........... n in N

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  7. If nP4 : nP5 = 1 : 2 then n = ............ .

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  8. If the repetation is not allowed then we get .......... total numbers ...

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  9. .........are the 9 digit numbers formed from the number with all digit...

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  10. ............are the total numbers words formed by the letters of the w...

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  11. The managing director of 'KUMAR PRAKASHAN KENDRA' arranges an exam of ...

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  12. n((n-1)P((r-1)))=................ .

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  13. ...........are the total numbers of ways to make a password of 5 digit...

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  14. ...........are the numbers of 7 digit formed by digits 3,4,5,4,5,5 and...

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  15. ""(n)Pr+((n),(r))=.........

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  16. If ((n),(12))=((n),(8)) then n = ........ .

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  17. If ""^(n)C(9)=""^(n)C(8), find ""^(n)C(17).

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  18. If ((20) ,(r))=((20),(r+2)) then ((r),(2))=........ .

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  19. Number of diagonal of the polygon having 10 sides = ............

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  20. The numbers of rectangle formed by m horizontal and n vertical line ar...

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