Home
Class 11
MATHS
If repetation is allowed then n objects ...

If repetation is allowed then n objects can be arranged in r places is n.r.

Text Solution

Verified by Experts

The correct Answer is:
False Statement
Promotional Banner

Topper's Solved these Questions

  • OBJECTIVE SECTION AS PER NEW PAPER SCHEME

    KUMAR PRAKASHAN|Exercise Binomial Theorem (Fill in the blanks )|16 Videos

  • OBJECTIVE SECTION AS PER NEW PAPER SCHEME

    KUMAR PRAKASHAN|Exercise Binomial Theorem (True /False Statement)|20 Videos

  • OBJECTIVE SECTION AS PER NEW PAPER SCHEME

    KUMAR PRAKASHAN|Exercise Permutations and Combinations (Fill in the blanks )|50 Videos

  • MATHEMATICAL REASONING

    KUMAR PRAKASHAN|Exercise QUESTION OF MODULE (Knowledge Test:)|2 Videos

  • PERMUTATIONS AND COMBINATIONS

    KUMAR PRAKASHAN|Exercise PRACTICE WORK |40 Videos

Similar Questions

Explore conceptually related problems

The number of permutations of n different objects, taken r at a line, when repetitions are allowed, is ……

If n denotes the number of ways of selecting r objects of out of n distinct objects (rgeqn) with unlimited repetition but with each objet included at least once in selection, then n m is equal is a. ^r-1C_(r-n) b. ^r-1C_n c. ^r-1C_(n-1) d. none of these

There are n different objects 1, 2, 3, …, n distributed at random in n places marked 1, 2, 3,…, n. If p be the probability that atleast three of the object occupy places corresponding to their number, then the value of 6p is

If n objects are arrange in a row, then the number of ways of selecting three of these objects so that no two of them are next to each other is a. ^n-2C_3 b. ^n-3C_2 c. ^n-3C_3 d. none of these

In an examination, a student has to answer 4 questions out of 5 questioins, questions 1 and 2 are however compulsory. Determine the number o f ways in which the student can make the choice . Thinking Process: We know that in selection of r objects out of given n objects if p objects are included then total numbers of selection are ((n-p),(r-p)).

A solid sphere of radius R and density rho is attached to one end of a mass-less spring of force constant k. The other end of the spring is connected to another solid sphere of radius R and density 3rho . The complete arrangement is placed in a liquid of density 2rho and is allowed to reach equilibrium. The correct statements(s) is (are)

n identical cells each of emf epsilon and lnternal resistance r are connected in parallel with resistor R. The current nowing through resistor R is ..........

An object is allowed to fall freely towards the earth from a distance r ( gt R_e) from the centre of the earth. Find the speed of the object when it strikes the surface of the earth.

Let R_(t) represents activity of a sample at an insant and N_(t) represent number of active nuclei in the sample at the instant. T_(1//2) represents the half life. {:(,"Column I",,"Column II"),((A),t=T_(1//2),(p),R_(t)=(R_(0))/(2)),((B),t=(T_(1//2))/(ln2),(q),N_(0)-N_(t)=(N_(0))/(2)),((C),t=(3)/(2)T_(1//2),(r),(R_(t)-R_(0))/(R_(0)) = (1-e)/(e)),(,,(s),N_(t)=(N_(0))/(2sqrt(2))):}

The sides of a square shaped frame, Shown in the diagram are made of wires of resistances r_(1) and r_(2) The frame is places in a uniform magnetic field, which is perpendicular to the plane of figure and is increasing at a constant rate. The resistance that should be connected across the diagonal of frame, so that this wire is warmed up at greatest rate is given by R=(n r_(1)r_(2))/(r_(1)+r_(2)) . Find n.

KUMAR PRAKASHAN-OBJECTIVE SECTION AS PER NEW PAPER SCHEME -Permutations and Combinations (True /False Statement)
  1. If an even can occur in m ways and corresponding to each way another e...

    Text Solution

    |

  2. If repetation is allowed then n objects can be arranged in r places is...

    Text Solution

    |

  3. n(A)= m, n (B) = n. The total number of non empty relation from A to B...

    Text Solution

    |

  4. Total numbers of 4 digits numbers using digits 5,2,3,7 and 8 are 620.

    Text Solution

    |

  5. (10!)/(8!) = 9 .

    Text Solution

    |

  6. 7 persons can sit on round table for discussion in 7! ways.

    Text Solution

    |

  7. ((n),(r))+((n),(r-1))=((n+1),(r-1))

    Text Solution

    |

  8. If ((n),(5))=((n),(13)) then ""^(n)C2 = ........

    Text Solution

    |

  9. The product of two consecutive positive integers is always divisible b...

    Text Solution

    |

  10. ((n),(r))+2.((n),(r-1))+((n),(r-2))=((n+2),(r))

    Text Solution

    |

  11. If an even can occur in m ways and corresponding to each way another e...

    Text Solution

    |

  12. If repetation is allowed then n objects can be arranged in r places is...

    Text Solution

    |

  13. Let n(A)=5 and n(B)=3 then find the number of injective functions and ...

    Text Solution

    |

  14. Total numbers of 4 digits numbers using digits 5,2,3,7 and 8 are 620.

    Text Solution

    |

  15. (10!)/(8!) = 9 .

    Text Solution

    |

  16. 7 persons can sit on round table for discussion in 7! ways.

    Text Solution

    |

  17. ((n),(r))+((n),(r-1))=((n+1),(r-1))

    Text Solution

    |

  18. If ((n),(5))=((n),(13)) then ""^(n)C2 = ........

    Text Solution

    |

  19. The product of two consecutive positive integers is always divisible b...

    Text Solution

    |

  20. ((n),(r))+2.((n),(r-1))+((n),(r-2))=((n+2),(r))

    Text Solution

    |