Particles of masses `1g, 2g, 3g,…. 100g` are kept at the marks `1cm, 2cm, 3cm,… 100cm` respectively on a meter scale. Find the moment of inertia of the system of particles about a perpendicular bisector of the meter scale.

Explanation

`[1xx49^(2)+2xx48^(2)+3xx47^(2)+…..49xx1^(2)+52xx2^(2)+…..98xx48^(2)+99xx49^(2)+100xx50^(2)]10^(-7)`
`=100[50^(2)+49^(2)+48^(2)+…..+1^(2)]xx10^(-7)`
`=10^(-5)xx(1)/(6)xx50xx51xx101=0.43kgm^(2)`