A uniform rod of mass m and length l is suspended by means of two light inextensible strings at the ends of rod. Tension in one string immediately after the other string is cut is

Explanation

`mg-T=ma`……….`(1)`
`alpha=(tau)/(I)=(mg.(l)/(2))/((ml^(2))/(3))=(3g)/(2I)`………..`(2)`
`a=(l)/(2)alpha`………`(3)`
Solving equations `(1)`, `(2)` and `(3)`
we get, `T=(mg)/(4)`