A door of moment of inertia `4kgm^(2)` is at rest. When a torque of `2piNm^("acts")` on it find its angular acceleration. Find also its angular velocity after `1`s .

Explanation

`alpha=(tau)/(I)=(2pi)/(4)=(pi)/(2)rad//s^(2)`
`omega_(2)-omega_(1)=alphat` `omega_(2)=(pi)/(2)xx1`
`omega_(2)=1.57rad//sec`