A thin rotates about an axis passing through its centre and perpendicular to its plane with a constant angular velocity `.omega.` I is the moment of inertia of that disc and .L. is its angular momentum about the given axis. Then rotational kinetic energy of the disc .E. is
(A) `E alpha L^(2)`
(B) `E alpha L^(-2)`
(C ) `E alpha I`
(D) `E alpha I^(-1)` (if L constant)

Options

A. A & C are correct
B. B & C are correct
C. B & D are correct
D. A & D are correct

Answer

D