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barF=abari+3barj+6bark and barr=2bari-6b...

`barF=abari+3barj+6bark` and `barr=2bari-6barj-12bark`. The value of 'a' for which the angular momentum is conserved is

A

`-1`

B

`0`

C

`1`

D

`2`

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The correct Answer is:
A
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