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If cot^(2)x =cot(x-y) cot(x-z), then cot...

If `cot^(2)x =cot(x-y) cot(x-z)`, then cot(2x) is equal to (where `x ne +-pi/4`)

A

`(cot x + cot y)/(2)`

B

`(cot y + cot z)/(2)`

C

`(cot x + cot z)/(2)`

D

`(cot x - cot z)/(2)`

Text Solution

Verified by Experts

The correct Answer is:
B
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