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sec["tan"^(-1)5+"tan"^(-1)1/5-"tan"^(-1)...

`sec["tan"^(-1)5+"tan"^(-1)1/5-"tan"^(-1)3/4]=`

A

`3//5`

B

`5//3`

C

`4//5`

D

`sqrt(2)`

Text Solution

Verified by Experts

The correct Answer is:
B
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