cos h (2) + sin h (2) =...

cos h (2) + sin h (2) =

A

`(1)/(e)`

B

e

C

`(1)/(e^(2))`

D

`e^(2)`

Text Solution

Verified by Experts

The correct Answer is:

D

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cosh(2) + sin h(2) =

A

`1//e`

B

e

C

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D

`e^(2)`

(cos h2 + sin h 2)^(n) =

A

`cos h(2n) + sin (2n)`

B

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C

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cos h 2x + sin h 2x =

A

`(1 + tan h(x))/(1- tan h(x))`

B

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C

`(tan h x -1)/(tan h x + 1)`

D

`(1 - tan hx)/(tan h x - 1)`

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