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Define f(x)={{:(x",",0lexle1),(2-x,,1lex...

Define `f(x)={{:(x",",0lexle1),(2-x,,1lexle2):}` then Rolles theorem is not applicable to f(x) because

A

f(x) is not defined every where on [0,2]

B

f(x) is not continuous on [0,2]

C

f(x) is not differentiable on (1,2)

D

f(x) is not differentiable on (0,2)

Text Solution

Verified by Experts

The correct Answer is:
D
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