Which of the following forms of hydrogen emits low energy β particles?

Options

A. Deuterium `""_(1)^(2)H`
B. Tritium `""_(1)^(3)H`
C. Protium `""_(1)^(1)H`
D. Proton `H^(+)`

Answer

To solve the question "Which of the following forms of hydrogen emits low energy β particles?", we need to analyze the different isotopes of hydrogen based on their neutron-to-proton (n/p) ratio. The isotopes of hydrogen are Protium (¹H), Deuterium (²H), and Tritium (³H).

### Step-by-Step Solution:

1. **Identify the Isotopes of Hydrogen**:
- Protium (¹H): 1 proton, 0 neutrons
- Deuterium (²H): 1 proton, 1 neutron
- Tritium (³H): 1 proton, 2 neutrons

2. **Calculate the n/p Ratio for Each Isotope**:
- **Protium (¹H)**:
- Number of protons (p) = 1
- Number of neutrons (n) = 0
- n/p ratio = n/p = 0/1 = 0

- **Deuterium (²H)**:
- Number of protons (p) = 1
- Number of neutrons (n) = 1
- n/p ratio = n/p = 1/1 = 1

- **Tritium (³H)**:
- Number of protons (p) = 1
- Number of neutrons (n) = 2
- n/p ratio = n/p = 2/1 = 2

3. **Compare the n/p Ratios**:
- Protium: n/p = 0
- Deuterium: n/p = 1
- Tritium: n/p = 2

4. **Determine Which Emits Low Energy β Particles**:
- The isotope with the highest n/p ratio emits the lowest energy β particles. Here, Tritium has the highest n/p ratio of 2.

5. **Conclusion**:
- Therefore, the form of hydrogen that emits low energy β particles is **Tritium (³H)**.

### Final Answer:
The correct option is **Tritium (³H)**.