In `overset(1)CH_(2)=overset(2)C=overset(3)CH-overset(4)CH_(3)` molecule, the hybridization of carbon 1,2,3 and 4 respectively are :

Options

A. `sp^(3),sp,sp^(3),sp^(3)`
B. `sp^(2),sp^(2),sp^(2),sp^(3)`
C. `sp^(2),sp,sp^(2),sp^(3)`
D. `sp^(2),sp^(3),sp^(2),sp^(3)`

Answer

To determine the hybridization of each carbon atom in the molecule `overset(1)CH_(2)=overset(2)C=overset(3)CH-overset(4)CH_(3)`, we will analyze the bonding and geometry around each carbon atom.

### Step-by-step Solution:

1. **Identify the Structure**:
The molecule can be represented as:
```
CH2 = C = CH - CH3
```
Here, we have four carbon atoms (C1, C2, C3, C4) connected by single and double bonds.

2. **Analyze Carbon 1 (C1)**:
- C1 is bonded to two hydrogen atoms and has a double bond with C2.
- This means C1 is involved in one double bond and has one single bond.
- Therefore, C1 is **SP² hybridized** (since it forms three sigma bonds).

3. **Analyze Carbon 2 (C2)**:
- C2 is bonded to C1 (double bond), C3 (double bond), and has no hydrogen atoms.
- C2 is involved in two double bonds.
- Therefore, C2 is **SP hybridized** (since it forms two sigma bonds).

4. **Analyze Carbon 3 (C3)**:
- C3 is bonded to C2 (double bond) and C4 (single bond), and has one hydrogen atom.
- C3 is involved in one double bond and one single bond.
- Therefore, C3 is **SP² hybridized** (since it forms three sigma bonds).

5. **Analyze Carbon 4 (C4)**:
- C4 is bonded to C3 (single bond) and three hydrogen atoms.
- C4 has only single bonds.
- Therefore, C4 is **SP³ hybridized** (since it forms four sigma bonds).

### Summary of Hybridization:
- Carbon 1 (C1): SP²
- Carbon 2 (C2): SP
- Carbon 3 (C3): SP²
- Carbon 4 (C4): SP³

### Final Answer:
The hybridization of carbon 1, 2, 3, and 4 respectively is: **SP², SP, SP², SP³**.