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A particle is projected with velocity V(...

A particle is projected with velocity `V_(0)`along axis x . The deceleration on the particle is proportional to the square of the distance from the origin i.e., `a=omegax^(2).`distance at which the particle stops is

A

`((3v_(0)^2)/(2alpha))^(1/2)`

B

`((2v_(0))/(3alpha))^(1/2)`

C

`((2v_(0)^2)/(3alpha))^(1/2)`

D

`((3v_(0)^2)/(2alpha))^(1/3)`

Text Solution

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The correct Answer is:
D
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