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A line through A (-5,-4) with slope ta...

A line through A (-5,-4) with slope `tantheta " meets the line " x+3y+2=0, 2x+y+4=0, x-y-5=0` at B,C,D respectivelly, such that `(15/AB)^2+(10/AC)^2 =(6/AD)^2` then

A

`15/AB=costheta+3sintheta`

B

`10/AC=2costheta+sintheta`

C

`6/AD= costheta-sintheta`

D

slope of the line `-(2)/3`

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The correct Answer is:
A, B, C, D
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