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A=[{:(1,2,2),(2,1,2),(2,2,1):}], then A^...

`A=[{:(1,2,2),(2,1,2),(2,2,1):}]`, then `A^(3) - 4A^(2) -6A` is equal to

A

0

B

A

C

`-A`

D

I

Text Solution

Verified by Experts

The correct Answer is:
C
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