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If 1/a+1/b+1/c=0 then |(1+a,1,1),(1,1+b,...

If `1/a+1/b+1/c=0` then `|(1+a,1,1),(1,1+b,1),(1,1,1+c)|=`

A

0

B

a b c

C

`-abc`

D

2 abc

Text Solution

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The correct Answer is:
B
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