In a ` Delta ABC ` , the distance of orthocentre ( O ) from the vertices A, B , C are x,y,z respectively show that x+ y+ z = 2 ( r + R )

The distance of the orthocentre from the vertices A,B,C are in the ratio

In a Delta ABC , if p,q,r are the distances from the orthocentre to the vertices A,B,C respectively, then a q r + b r p+ c p q =

In Delta ABC is H is the orthocentre of Delta ABC and x= AH, y=BH, z=CH, then x+y+z=

In a triangle XYZ, let x,y,z be the lengths of sides opposite to the angles X, Y, Z, respectively, and 2s = x + y + z . " If" (s - x)/4 = (x - y)/3 = (x - z)/2 and area o incircle of the triangle XYZ is (8pi)/3 , then

if x,y,z are the distances of the vertices of Delta ABC from its orthocentre then x+y+z ' is

Consider a triangle ABC, where x, y, z are the length of perpendicular drawn from the vertices of the triangle to the opposite sides a, b, c respectively let the letters R, r, S, D denote the circumradius. inradius semi-perimeter and area of the triangle respectively. The value of (c sin B + b sin C)/x + (a sin C + c sin A)/y + (b sin A + a sin B)/z is equal to

Consider a triangle ABC, where x, y, z are the length of perpendicular drawn from the vertices of the triangle to the opposite sides a, b, c respectively let the letters R, r, S, D denote the circumradius. inradius semi-perimeter and area of the triangle respectively. If (bx)/c + (cy)/a + (az)/b = (a^(2) + b^(2) + c^(2))/k then the value of k is

If H is the orthocentre of DeltaABC and AH=x, BH=y, CH=z then (abc)/(xyz)=