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In a triangle ABC, C=90^@. Then (a^2-b^2...

In a triangle ABC, `C=90^@`. Then `(a^2-b^2)/(a^2+b^2)`=

A

` sin (A+ B) `

B

` sin ( A-B) `

C

` cos ( A+B) `

D

` cos ( A- B) `

Text Solution

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The correct Answer is:
B
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