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AB is vertical pole with B at ground level and A at the top. A man finds that the angle of elevation of the point A from a certain point C on the ground is `60^(@)`. He moves away from the pole along the line BC to a point D such that CD =7 m. From D the angle of elevation of the point A is `45^(@)` then the hight of the pole is

A

` ( 7sqrt3)/(2) ( sqrt3- 1) `

B

` ( 7sqrt3)/(2) ( sqrt3+ 1) `

C

` 7sqrt3`

D

` ( 7sqrt3)/(2) `

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The correct Answer is:
B
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AAKASH SERIES-PROPERTIES OF TRIANGLES-EXERCISE - II
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