A boy recalls the relativistic mass wrongly as `m=m_0/sqrt(1-V^2)`
Using dimensional method put the missing 'C' at proper place.

A famous relation in physics relates 'moving mass' m to the 'rest mass' m_0 of a particle in terms of its speed v and the speed of light c. (This relation first arose as a consequence of special relativity due to Albert Einstein). Boy recalls the relation almost correctly but forgets where to put the constant c. He writes: m_0/(1-v^2)^(1/2) Guess where to put the missing c.

Consider two point masses, m_1 and m_2 , moving along a straight line in the same direction with speeds u_1 , and u_2 . Let them undergo one-dimensional collision and retrieve each other with velocities v_1 and v_2 .how that ( u_1 - u_2 ) = - ( v_1 - v_2 ) i.e, after collision, their relative velocities are equal.

in a particular experiment Ramu use the relation F=AB+(P+Q)Y to calculate force. in the dimensional formula of Y is M^0L^1T^(-1). then find the dimensional formula of P.