Home
Class 12
MATHS
A balanced dice is tossed twice. Find pr...

A balanced dice is tossed twice. Find probability on an event that on first trial we get number 4, 5 or 6 and in second trial we get number 1, 2, 3 or 4.

Text Solution

Verified by Experts

The correct Answer is:
`(1)/(3)`
Promotional Banner

Topper's Solved these Questions

  • PROBABILITY

    KUMAR PRAKASHAN|Exercise EXERCISE -13.1 |23 Videos
  • PROBABILITY

    KUMAR PRAKASHAN|Exercise EXERCISE -13.2 |30 Videos
  • MATRICES

    KUMAR PRAKASHAN|Exercise Practice Paper - 3 (Section - D)|1 Videos
  • RELATIONS AND FUNCTIONS

    KUMAR PRAKASHAN|Exercise Practice Paper - 1 (Section - D)|2 Videos

Similar Questions

Explore conceptually related problems

A balanced dice is tossed thrice. Find probability of getting an odd number at least once.

A balanced dice is tossed (2n + 1) times. Find probability of an event that number 1 OR 3 OR 4 comes up at most n times.

A dice is tossed twice. Find probability of getting a number greater than 3 on each toss.

A die is tossed thrice. Find the probability of getting an odd number at least once.

Nine balanced coins tossed together once. Find probability of getting at least 6 heads.

Two balanced dice are tossed. Find probability of the event that sum of the numbers obtain on both dice is 3 or it is multiple of 5.

A pair of dice is tossed simultaneously. Find the probability of getting the product of the numbers on dice to be 12.

Consider the random experiment of tossing dice. If number obtained on it is multiple of 3 then toss dice again, and if any other number is obtained toss a coin. Find probability of an event that coin shows tail given that at least once number 2 comes up.

A die is rolled once. Find the probability of getting (i) a prime number (ii) a number lying between 2 and 6 (iii) an odd number