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`omega` is the cube root of 1 and `omega ne 1`. Now `r_(1), r_(2)` and `r_(3)` are the number obtained while tossing dice thrice. Then ………… is the probability for `omega^(r^(1)) +omega^(r^(2))+omega^(r^(3))=0`

A

`(1)/(18)`

B

`(1)/(9)`

C

`(2)/(9)`

D

`(3)/(36)`

Text Solution

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The correct Answer is:
C
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