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In squareABCD , side BC|| side AD. Digon...

In `squareABCD` , side `BC||` side `AD`. Digonals `AC` and `BD`
intersect each other at `P`. If `AP=(1)/(3)AC` then prove `DP=(1)/(2)BP`.

Text Solution

Verified by Experts

The correct Answer is:
`:.DQ=(1)/(2)BQ`
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