Home
Class 10
MATHS
In triangle ABC , angle BAC = 90^(@) ...

In ` triangle ABC , angle BAC = 90^(@) ` , seg BL and seg CM are medians of ` triangle ABC ` . Then prove that
` 4 (BL^(2) + CM^(2)) = 5 BC^(2)`

Text Solution

Verified by Experts

The correct Answer is:
`therefore4(BL^(2)+CM^(2))=5BC^(2)`
Promotional Banner

Topper's Solved these Questions

  • PYTHAGORAS THEOREM

    TARGET PUBLICATION|Exercise Problem set-26|1 Videos

  • PYTHAGORAS THEOREM

    TARGET PUBLICATION|Exercise Problem set-27|1 Videos

  • PYTHAGORAS THEOREM

    TARGET PUBLICATION|Exercise Problem set-2|8 Videos

  • PROBABILITY

    TARGET PUBLICATION|Exercise Try This|1 Videos

  • QUADRATIC EQUATIONS

    TARGET PUBLICATION|Exercise Chapter Assessment|39 Videos

Similar Questions

Explore conceptually related problems

If in a triangle ABC, b=sqrt3 , c=1 and B-C=90^0 , then angle A is

Draw triangle ABC ,AB=AC=4 cm,BC=6 cm.

Seg AM is a median of triangle ABC . If AB=22, AC=34, BC=24, find AM.

In DeltaABC , /_ABC=90^(@) , AB=12 , BC=16 and seg BP is the median drawn to side AC . Find the length of seg BP .

In triangle ABC, AB^2+AC^2=122 and BC=10. Find the length of the median of side BC.

In a triangle ABC, if sin A sin B= (ab)/(c^(2)) , then the triangle is :

In triangle ABC , seg AD_|_side BC , B-D-C. Prove that AB^2+CD^2=BD^2+AC^2

If in a triangle ABC, 2cosA=sinBcosecC , then

In triangle ABC , /_B=90^@ and AB = BC. If AC = 2sqrt2 , then find AB and BC.