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When light of frequency v1 incident on a...

When light of frequency `v_1` incident on a metal with work function `W_0` (where `hv_1 gt W_0),` the photocurrent falls to zero at a stopping potential of `V_1.` If the frequency of light is increased to `v_2,` the stopping potential changes to `V_2.` Therefore, the charge of an electron is given by

A

`(W_0 (v_2 +v_1))/(v_1 V_2 +v_2V_1)`

B

`(W_0 (v_2 +v_1))/(v_1V_1 +v_2 V_2)`

C

`(W_0(v_2 -v_1))/(v_1 V_2-v_2 V_1)`

D

`(W_0 (v_2-v_1))/(v_2 V_2-v_1V_1)`

Text Solution

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The correct Answer is:
C
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