Two identical photo-cathodes receive light of frequencies `f_1` and `f_2`. If the velocities of the photoelectrons (of mass m) coming out are `v_1` and `v_2` respectively, then

Options

A. `v_1^2-v_2^2=(2h)/(m)(f_1-f_2)`
B. `v_1 +v_2 =[(2h)/(m)(f_1 -f_2)]^(1//2)`
C. `v_1^2-v_2^2=(2h)/(m)(f_1 +f_2)`
D. `v_1 -v_2 =[(2h)/(m) (f_1-f_2)]^(1//2)`

Answer

A