A cell with 2n=16 undergoes meiosis. Each of the four daughter nuclei formed at the end of the division will have

Options

A. 4 chromosomes- double stranded
B. 8 chromosomes- single stranded
C. 8 chromosomes-double stranded
D. 4 chromosomes- single stranded

Answer

To solve the question regarding a cell with 2n = 16 undergoing meiosis, we can break it down into the following steps:

### Step-by-Step Solution:

1. **Identify the Chromosome Number**:
The given cell has a diploid number of chromosomes represented as 2n = 16. This means that the total number of chromosomes in the parent cell is 16.

2. **Determine the Haploid Number**:
To find the haploid number (n), we divide the diploid number by 2.
\[ n = \frac{2n}{2} = \frac{16}{2} = 8 \]
Therefore, each daughter cell will have 8 chromosomes.

3. **Understand Meiosis Process**:
Meiosis consists of two rounds of division: Meiosis I and Meiosis II.
- In Meiosis I, homologous chromosomes are separated, reducing the chromosome number by half.
- In Meiosis II, the sister chromatids of each chromosome are separated.

4. **Determine the Chromosome Structure**:
After Meiosis I, each daughter cell has 8 chromosomes, but they are still in the form of sister chromatids (double-stranded).
After Meiosis II, each of the 8 chromosomes will separate into single chromatids (single-stranded).

5. **Final Count of Daughter Nuclei**:
At the end of meiosis, we have 4 daughter nuclei, each containing:
- 8 chromosomes (haploid)
- Each chromosome is now single-stranded.

6. **Conclusion**:
Therefore, each of the four daughter nuclei formed at the end of meiosis will have 8 chromosomes, and they will be single-stranded.

### Final Answer:
Each of the four daughter nuclei formed at the end of meiosis will have **8 chromosomes single-stranded**.

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