Consider a certain reaction `A to` Products with `k=2.0xx10^(-2)s^(-1)`. Calculate the concentration of A remaining after 100 s if the initial concentration of A is 1.0 `mol L"^(-1)`.

Explanation

The units of k indicate that the reaction is of first order.
Hence, `k=(2.303)/(t)"log"([A]_(0))/([A])`
Substituting the values, we get
`2.0xx10^(-2)s^(-1)=(2.303)/(100s)"log"(1.0"mol L"^(-1))/([A])`
or `log[A]= -0.8684`
or ` [A]="Antilog" (-0.8684)="Antilog"(bar1.1316)=0.1354" mol L"^(-1)`.