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In a common emitter transistor, the base...

In a common emitter transistor, the base current ` I_(b) = 2 mu A, alpha = 0.9 , ` then `I_(c)` is equal to

A

18 `mu A `

B

` 20 mu A `

C

` 22 mu A `

D

`24 mu A `

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The correct Answer is:
A
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