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The electric field part of an electromag...

The electric field part of an electromagnetic wave in a medium is represented by
` E_(x) = 0, `
` E _(y)= 2.5 (N)/( C) cos [(2 pi xx 10^(6) rad/s ]t - ( pi xx 10^(-2) (rad)/m) x]`
` E_(z) = 0`
The wave is

A

moving along the + x direaction with frequency ` 10^(6)` Hz and wavelength 100 m .

B

moving along + x direction with frequency ` 10^(6) ` Hz and wavelength 200 m .

C

moving along-x direction with frequency ` 10^(6)` Hz and wavelength 200 m .

D

moving along + y direction with frequency ` 2 pi xx 10^(6)` Hz and wavelength 200 m .

Text Solution

Verified by Experts

The correct Answer is:
A
Given . ` E_(x) = 0`
` E_(y) = 2.5 N/C cos [(2pi xx 10^(6) (rad)/s) t - ( pi xx 10^(-2) (rad)/m)x]`
This shows that the wave is propagating along + direction. Comparing the given equation with ` E_(y) = E_(0)cos(omegat - kx),` we get
` omega =2 pi xx 10^(6) or v = 10^(6) Hz `
` and k = pi xx 10^(6) or 2 pi v = 10^(-2) m `
` or lamda = ( 2pi)/( pi xx 10^(-2)) = 200 m`
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