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Let the position vectors of the points A, B and C be `vec(a),vec(b)andvec(c)` respectively. Let Q be the point of intersection of the medians of the triangle ABC. Then `vec(QA)+vec(QB)+vec(QC)=`

A

`(vec(a)+vec(b)+vec(c))/(2)`

B

`2vec(a)+vec(b)+vec(c)`

C

`vec(a)+vec(b)+vec(c)`

D

`vec(0)`

Text Solution

Verified by Experts

The correct Answer is:
D
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