A body weighs one Newton at the surface of the earth. What will be it’s weight at a height equal to half the radius of the earth ?

Explanation

`g^'/g=(GM)/(R+h)^2xxR^2/(GM)=R^2/(R+R/2)^2
therefore=((R^2xx4)/(9R_2))g=4/9g
"Force" `=72xx4/9=32 N`