The body weighs 100 N on the surface of the earth, then how much it would weigh at a depth of R/2 below the surface of the earth at radius R.

Explanation

`T_1=2pisqrt(l/g)thereforeg'=g/((1+R/R)^2 )=3/4
thereforeT_2=2pisqrt((4l)/g)therefore T_1//T_2sqrt((4l)/gxxg/l)=2`