The distance from the earth's surface at which the acceleration due to gravity equals to `1m/s^2` is about

Explanation

Mass of the earth `VxxP=4//3pir^3rho g=GM//R^2=G/R^2(4/3piR^3rho)=4//3piRGrho`
Thus, `galpharho` since R S G are constant . If `rho` is doubled, then g'=2g=2xx98=19.6m//s^2`