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The body weighs 100 N on the surface of ...

The body weighs 100 N on the surface of the earth, then how much it would weigh at a depth of R/2 below the surface of the earth at radius R.

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`g'=gR^2/((R+R//2)^2 )=4/9g
thereforeW'=mg'=4/9mg=4/9W`.
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