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Calculate e.m.f. of cell for the reactio...

Calculate e.m.f. of cell for the reaction :
`Mg_((s))+Cu^(2+)"(0.0001 M)"rarr Mg^(2+)"(0.001 M)"+Cu_((s))`
Given that : `E_(Mg^(2+)//Mg)^(@)=-2.37V`
`E_(Cu^(2+)//Cu)^(@)=+0.34V`

Text Solution

Verified by Experts

`E_("cell")=E_(Cu^(+2)//Cu^(-))^(@)-E_(mg^(+2)//mg)^(@)-(RT)/(2F)log""([Mg^(+2)])/([Cu^(+2)])=0.34-(-2.37)-(0.59)/(2)log_(10)""(10^(-3))/(10^(-4))`
`E_("cell")=2.71-(0.59)/(2)log_(10)10`
`E_("cell")=2.68V`
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SUNSTAR PUBLICATION-ANNUAL EXAM QUESTION PAPER MARCH - 2018-PART - D
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