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(tan^(2)2theta-tan^(2)theta)/(1-tan^(2)2...

`(tan^(2)2theta-tan^(2)theta)/(1-tan^(2)2thetatan^(2)theta)=`

A

`tan3theta cottheta`

B

`cot3theta tantheta`

C

`cot3theta cottheta`

D

`tan3theta tantheta`

Text Solution

Verified by Experts

The correct Answer is:
D
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