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If A=6 sin20^(@) - 8 sin^(3) 20^@ , B= ...

If ` A=6 sin20^(@) - 8 sin^(3) 20^@ , B= 8 cos^(3) 20^(@)-6 cos 20^(@) and C= ( sin 3 theta )/( sin theta ) - ( cos 3 theta )/( cos theta ) ` then

A

`CgtAgtB`

B

`AgtBgtC`

C

`AgtCgtB`

D

`CgtBgtA`

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The correct Answer is:
A
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