Compute the following limits : Lt(xto0...

Compute the following limits :
`Lt_(xto0)(1-cosx)/x^(2)`

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Verified by Experts

The correct Answer is:

`1//2`

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AAKASH SERIES-LIMITS-EXERCISE-2.3 (SHORT ANSWER QUESTIONS)

Find Lt(x to a) ((x sin a - a sin x)/(x -a))
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Compute the following limits : Lt(xto0)(1-cosx)/x^(2)
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Find {:(" Lt"),(xrarr0):}(sin(a+bx)-sin(a-bx))/(x)
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Evaluate {:(" Lt"),(xrarr0):}(xtan2x-2xtanx)/((1-cos2x)^(2))
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Compute the following limits : Lt(xto0)(e^(x)-sinx-1)/x
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Show that Lt(xto0)(1-cos2mx)/(sin^(2)nx)(m,ninz)=2(m/n)^(2)
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Show that Lt(xto0)(1-cosax)/(xsin2x)=a^(2)/4
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Show that Lt(xto0)(cosecx-cotx)/x=1/2
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Show that Lt(xtoa)(sin(x-a)tan^(2)(x-a))/((x^(2)-a^(2))^(3))=1/(8a^(...
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Show that Lt(xto0)(cosax-cosbx)/x^(2)=(b^(2)-a^(2))/2
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Show that Lt(xto0)(1-cosmx)/(1-cosnx)=m^(2)/n^(2),n ne0
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underset(x to pi//2)lim (1-sin^(3)x)/(cos^(2)x)=
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Evaluate the following Lt(xto0)(tanx-sinx)/x^(3)
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Evaluate the following Lt(xto0)(2x//(tan2x))
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Evaluate Lt(x to 0)("sec" x - 1)/(x^2)
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Evaluate Lt(xto0)(3sinx^(0)-sin3x^(0))/x^(3)
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Evaluate Lt(xto0)(tanx^(0))/x^(0)
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Evaluate Lt(xto0)(1-cos(x))/x^(2)
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