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An electron in hydrogen atom experiences...

An electron in hydrogen atom experiences a transition from n = 6 to n = 3. Find out the frequency of the radiation.

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Wave number of radiation emitted in H atom,
`(1)/(lambda)=R[(1)/(3^(2))-(1)/(6^(2))]=R[(1)/(9)-(1)/(36)]`
`(1)/(lambda)=(27R)/(324)=(R)/(12)....(1)`
`rArr` Now
`c=lambda v`
`:.(1)/(lambda)=(v)/(c)`
`:.(v)/(c)=(R)/(12)[ :.` From equation (1)]
`:.v=(Rc)/(12)=(1.09xx10^(7)xx3xx10^(8))/(12)`
`:.v=0.275xx10^(15)Hz`
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