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Acceleration of a car in motion is 1.5 m...

Acceleration of a car in motion is `1.5 m s^(-2).` How much is the increase in velocity in 4s?

A

`6 ms^(-1)`

B

`4 ms ^(-1)`

C

`4 ms ^(-1)`

D

`2.66 ms ^(-1)`

Text Solution

Verified by Experts

The correct Answer is:
A

Acceleration`= ("Change in velocity")/("Time interval")`
`therefore` Change in velocity (increase)
= Acceleration `xx` Time interval
`= (1.5 ms ^(-2)) xx (4s)`
`=6 ms ^(-1)`
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