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A+B + C = 2S implies sin S + sin (S -A) ...

`A+B + C = 2S implies sin S + sin (S -A) + sin (S - B) - sin (S - C) =`

A

`4cos""(A)/(2) .cos ""(B)/(2) .cos""(C )/(2)`

B

`4cos ""(A)/(2).cos""(B)/(2) .sin""(C )/(2)`

C

`4 cos ""(A)/(2).sin""(B)/(2) .cos ""(C )/(2)`

D

`4 sin "" (A)/(2) .sin ""(B)(2) .sin""(C )/(2)`

Text Solution

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The correct Answer is:
B
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